Chapter V

Mechanical Power Transmission Systems

Red Seal Practice study guide with diagrams.

Mechanical Power Transmission Systems

Chapter Introduction

This chapter covers all mechanical power transmission systems you must master for the Red Seal exam. As an industrial mechanic (millwright), you will be called upon to install, align, troubleshoot, and replace these components. The exam evaluates not only your ability to identify components, but also your understanding of physical principles, speed and torque calculations, alignment procedures, and safety requirements. This chapter is structured to follow a logical progression: from fundamental principles to practical applications, with special attention to common pitfalls.


Fundamental Principles of Power Transmission

Definition and Role

Mechanical power transmission is the set of devices that transfer mechanical energy from a source (electric motor, internal combustion engine, turbine) to a receiving machine (pump, compressor, conveyor). The role of the industrial mechanic is to ensure that this transmission occurs with optimal efficiency, minimal wear, and maximum safety.

Fundamental Parameters: Speed, Torque, and Power

Three physical quantities govern all transmission systems:

Rotational speed (N): expressed in revolutions per minute (RPM). This is the rotational frequency of the shaft.
Torque (T): expressed in newton-metres (N·m) or pound-feet (lb·ft). This is the moment of force that tends to rotate the shaft.
Power (P): expressed in watts (W), kilowatts (kW), or horsepower (hp). This is the rate at which work is performed.

The fundamental relationship is:

P = T × Ω

Where Ω (omega) is the angular velocity in radians per second (rad/s). The conversion between RPM and rad/s is:

Ω = (2 × π × N) / 60

In practice, for quick calculations, you will often use:

P (kW) = T (N·m) × N (RPM) / 9550

P (hp) = T (lb·ft) × N (RPM) / 5252

Transmission Ratio

The transmission ratio (i) is the ratio between the input speed and the output speed of a system:

i = N₁ / N₂ = D₂ / D₁ = Z₂ / Z₁

Where:

N₁ = input speed, N₂ = output speed
D₁ = diameter of the driving pulley, D₂ = diameter of the driven pulley
Z₁ = number of teeth on the driving sprocket, Z₂ = number of teeth on the driven sprocket

Golden rule: in a transmission system, the product of torque × speed is constant (neglecting losses). If speed decreases, torque increases proportionally.


Drive Belts

V-Belts — Power Transmission V-Belts — Power Transmission Schematic Diagram DRIVING (Driver) DRIVEN (Driven) V-Belt Trapezoidal Tension Cross-section — V-Groove 36°–40° The belt rests on the flanks of the groove — not on the bottom. Wedge grip Advantages • Quiet operation • Protects against overloads • No lubrication required • Low installation cost • Tolerates slight misalignment • Shock absorption • Accurate speed ratio Disadvantages • Progressive wear • Possible slippage • Limited center distance • Heat sensitivity • Requires a tensioner • Reduced lifespan • Limited max speed Storage and Inspection Store away from light and oil Inspect: cracks, fraying, glazing Tension: deflection of 15 mm per meter (1/4") Replace belts in matched sets — never mix Warning (Red Seal) Disconnect power (Lockout/Tagout) before any maintenance on belts and pulleys.

Types of Belts

TypeCharacteristicsTypical Applications
**Flat belt**Rectangular cross-section, large contact surfaceHigh-speed machinery, long-distance transmission
**V-belt**V-shaped cross-section, better grip in the grooveGeneral purpose, conveyors, compressors
**Timing belt (synchronous)**Teeth that mesh with the pulley, no slippageApplications requiring exact synchronization (camshafts, printers)
**Poly-V belt (micro-V)**Multiple longitudinal ribs, flexibleHigh-speed applications, compact spaces
**Round belt**Circular cross-section, used in light systemsSmall machines, low-power drives

V-Belts: Designations and Dimensions

V-belts are designated by their cross-section (A, B, C, D, E) according to standards. The nominal dimensions are:

SectionWidth (mm)Height (mm)Typical Power Range
A1380.5 to 7 kW
B17111 to 15 kW
C22145 to 40 kW
D321915 to 100 kW
E382330 to 200 kW

Belt Length Calculation

For a V-belt, the pitch length (Lp) is calculated as:

Lp = 2C + (π/2) × (D₁ + D₂) + (D₂ − D₁)² / (4C)

Where:

C = centre distance (distance between the centres of the two pulleys)
D₁ = pitch diameter of the smaller pulley
D₂ = pitch diameter of the larger pulley

Common pitfall: the pitch length is not the outside length. Belts are measured on their pitch diameter, which is located approximately at the centre of the cross-section.

Belt Tension

Correct tension is essential. A belt that is too loose will slip and overheat; a belt that is too tight will overload bearings and reduce service life.

Deflection method: apply a perpendicular force at the midpoint of the free span. The deflection should be approximately 1/64 of an inch per inch of free span (approximately 1.5 mm per 100 mm). The force to apply depends on the belt cross-section.

Rule of thumb: the deflection should be approximately equal to the belt thickness for correct tension.

Pulley Alignment

Pulley alignment is critical. Poor alignment causes premature wear, vibration, and power loss. Use:

A straightedge or taut string to check parallel alignment
A laser level for precision alignment
A dial indicator to check pulley runout

Requirement: pulley faces must be in the same plane with a tolerance of ±0.5 mm for V-belts.


Drive Chains

Types of Chains

TypeCharacteristicsApplications
**Roller chain (ANSI)**Most common, rollers on bushingsConveyors, machine tools, industrial drives
**Bush chain**Similar but without rollersLow-speed applications
**Silent chain (inverted tooth)**Flat teeth, quiet operationHigh-speed, precision applications
**Lifting chain**Oval links, high strengthLifting, material handling

Roller Chain Designations

ANSI chains are designated by a number: the first digit indicates the pitch in eighths of an inch, the second digit indicates the type (0 = standard, 1 = light, 5 = heavy).

Examples:

40: pitch of 4/8 = 1/2 inch (12.7 mm), standard
60: pitch of 6/8 = 3/4 inch (19.05 mm), standard
80: pitch of 8/8 = 1 inch (25.4 mm), standard

Chain Length Calculation

Chain length is expressed as the number of links. For a chain drive:

L = (2C/P) + (Z₁ + Z₂)/2 + (Z₂ − Z₁)² / (4π² × C/P)

Where:

L = number of links
C = centre distance in mm
P = chain pitch in mm
Z₁ = number of teeth on the driving sprocket
Z₂ = number of teeth on the driven sprocket

Important rule: the number of links must be a whole number. If the calculation gives a fractional number, round up to the next whole number and adjust the centre distance.

Chain Tension and Alignment

The recommended sag for a chain is approximately 2 to 4% of the centre distance (measured at the midpoint of the free span). A tensioner may be necessary if the centre distance is not adjustable.

Alignment: sprockets must be in the same plane with a tolerance of ±0.25 mm. Angular misalignment of more than 1° is unacceptable.

Chain Lubrication

Lubrication is essential for service life. Methods range from manual lubrication (low speed) to oil bath or spray lubrication (high speed). The general rule:

Speed < 3 m/s: manual or drip lubrication
Speed 3 to 7.5 m/s: oil bath or splash lubrication
Speed > 7.5 m/s: pressurized oil spray lubrication

Gears

Types of Gears

TypeCharacteristicsApplications
**Spur gear**Teeth parallel to the axis, simple, noisyLow and medium speeds
**Helical gear**Inclined teeth, quiet operation, axial thrustHigh speeds, power transmission
**Bevel gear**Teeth on a cone, transmits at right anglesAngle drives
**Herringbone gear**Double helix, no axial thrustVery high power
**Worm gear and wheel**High ratio, irreversible, low efficiencyBrakes, winches, lifting systems

Gear Ratio and Torque

For a pair of gears:

i = Z₂ / Z₁ = N₁ / N₂

The output torque is:

T₂ = T₁ × i × η

Where η is the efficiency (typically 0.95 to 0.98 for spur gears, 0.85 to 0.90 for worm gears).

Backlash

Backlash is the space between the tooth flanks of two meshing gears. It is necessary to:

Compensate for thermal expansion
Allow for lubrication
Prevent jamming

Typical backlash is 0.05 to 0.15 mm for standard industrial gears. Excessive backlash causes noise and shock loads; insufficient backlash causes overheating and rapid wear.

Gear Installation

When installing a pair of gears:

100.Verify that the shafts are parallel (tolerance: 0.02 mm per 100 mm)
101.Verify the centre distance (tolerance: ±0.05 mm)
102.Check backlash with a feeler gauge or dial indicator
103.Check tooth contact with marking compound (contact must cover at least 70% of the tooth width)

Couplings

Role and Classification

A coupling connects two shafts to transmit torque while compensating for alignment defects. Types include:

TypeCompensationApplications
**Rigid**NonePerfectly aligned shafts
**Elastic (rubber, elastomer)**Moderate misalignment, absorbs shockPumps, fans, compressors
**Gear**Angular and parallel misalignmentHigh power, high speeds
**Bellows**Small misalignment, high torqueServomotors, precision machinery
**Spider (jaw)**Moderate misalignment, easy to replaceSmall and medium power
**Hydraulic**Shock absorption, torque limitingShock-load applications

Coupling Alignment

Alignment is one of the most critical operations in the trade. Methods:

111.Straightedge and feeler gauge method: straightedge on the circumference, feeler gauge between the faces. Accuracy: ±0.1 mm.
112.Dial indicator method: two indicators mounted on a bracket, measuring radial and axial misalignment. Accuracy: ±0.02 mm.
113.Laser alignment: the most accurate and fastest method. Accuracy: ±0.005 mm.

Typical tolerances (according to ISO 1940 and manufacturer recommendations):

Machine TypeSpeed (RPM)Max Parallel MisalignmentMax Angular Misalignment
Slow machines< 10000.10 mm0.10 mm/100 mm
Medium machines1000-36000.05 mm0.05 mm/100 mm
Fast machines> 36000.02 mm0.02 mm/100 mm

Dial Indicator Alignment Procedure

117.Mount the indicator bracket on one shaft, with the indicators on the other.
118.Rotate both shafts together in 90° increments.
119.Record readings at 0°, 90°, 180°, 270°.
120.Calculate misalignment: the difference between opposite readings divided by 2 gives the radial misalignment.
121.Adjust the machine position using shims under the feet.
122.Repeat until readings are within tolerances.

Common pitfall: never align a machine cold when it operates hot. Thermal expansion moves the shaft; you must account for a "thermal offset" (usually provided by the manufacturer).


Gearboxes and Speed Reducers

Types of Reducers

TypeTypical RatioEfficiencyApplications
**Spur gear reducer**2:1 to 10:195-98%General purpose
**Helical gear reducer**5:1 to 50:194-97%Conveyors, mixers
**Worm gear reducer**10:1 to 100:170-90%Winches, positioners
**Planetary reducer**3:1 to 100:195-98%Servomotors, robots
**Mechanical variable speed drive (PIV)**Variable90-95%Variable-speed machinery

Calculating Reducer Output Torque

T₂ = T₁ × i × η

Example: a 5 kW motor at 1750 RPM drives a 20:1 reducer with 92% efficiency.

T₁ = (9550 × 5) / 1750 = 27.3 N·m
T₂ = 27.3 × 20 × 0.92 = 502.3 N·m
N₂ = 1750 / 20 = 87.5 RPM

Checking Thermal Capacity

A reducer may be limited by its thermal capacity (heat dissipation) rather than its mechanical capacity. If the oil temperature exceeds 90 °C, you must:

Increase ventilation
Add a cooler
Reduce the load or speed

Transmission Shafts and Bearings

Shafts

Transmission shafts transmit torque and support loads. Design criteria include:

Torsional strength (shear stress)
Bending strength (normal stress)
Maximum allowable deflection
Critical speed (avoid resonance)

Torsional stress:

τ = (16 × T) / (π × d³)

Where τ = shear stress (Pa), T = torque (N·m), d = shaft diameter (m).

Bearings

TypeRadial LoadAxial LoadSpeedApplications
**Radial contact ball bearing**GoodLowVery highMotors, pumps
**Cylindrical roller bearing**Very goodLowHighGearboxes
**Tapered roller bearing**Very goodVery goodMediumWheels, differentials
**Ball thrust bearing**NoneVery goodMediumVertical shafts
**Needle bearing**GoodLowMediumConfined spaces

Bearing Installation

Hot installation: heat the bearing in an oven or oil bath to 80-120 °C (never above 125 °C). Never use a torch directly on the bearing.

Cold installation: use a press or a mounting tube that presses on the inner race (never on the outer race for a shaft mounting).

Internal clearance: a bearing's internal clearance decreases when mounted with interference. Negative clearance (preload) can cause overheating.


Applicable Standards and Codes

Canadian Electrical Code (CE Code)

The Canadian Electrical Code, Part I (CE Code) (CSA C22.1) applies to electrical installations, including motors and their protection. Relevant points:

Rule 28-300: Motor overload protection. The protective device must be set at 125% of the full-load current for continuously rated motors.
Rule 28-308: Short-circuit protection. The fuse or circuit breaker must be sized according to Table 29.
Rule 28-602: Size of motor supply conductors.

Although this code is electrical, the industrial mechanic must know these rules because you work in interface with motors.

CSA B149.1 (Natural Gas and Propane Installation Code)

This code applies to gas installations, including gas engines and compressors. Relevant points:

Ventilation of rooms containing combustion engines
Gas leak detection
Safety distances from sources of ignition

CSA Machinery Standards

CSA Z432: Safeguarding of machinery (machine guarding). This standard defines requirements for guards and safety devices.
CSA Z460: Lockout — control of hazardous energy.

Relevant ISO Standards

ISO 1940: Balancing of shafts and rotors (balancing quality G).
ISO 10816: Evaluation of machine vibration.
ISO 4183: V-belts — pulley grooves.

Safety Procedures

Lockout/Tagout

Before any intervention on a transmission system:

180.Identify all energy sources (electrical, hydraulic, pneumatic, mechanical).
181.Stop the machine.
182.Isolate the energy sources (open the disconnect switch, close the valves).
183.Apply the lock and tag (compliant with CSA Z460).
184.Dissipate residual energy (discharge accumulators, wait for complete stop).
185.Verify the absence of energy (test start).

Machine Guards

All transmission elements (belts, chains, gears, couplings) must be protected by guards compliant with CSA Z432:

Minimum distance between the guard and the moving part
Impact-resistant material
Fastening that requires a tool to remove
Must not create new pinch points

Rotor Balancing

Balancing is necessary for pulleys, rotors, and flywheels. The balancing quality G is defined by ISO 1940:

Quality GTypical Applications
G 6.3Fans, pumps, agricultural machinery
G 2.5Electric motors, turbines, machine tools
G 1.0Compressors, precision machinery
G 0.4Gyroscopes, high-precision spindles

Pitfalls to Avoid

197.Confusing pitch diameter and outside diameter of pulleys. The transmission ratio is calculated on pitch diameters, not outside diameters.
198.Forgetting efficiency in torque calculations. A worm gear reducer has an efficiency of 70-90%; neglecting this factor gives an overestimated output torque.
199.Using the outside length instead of the pitch length for belts. The difference can be 20 to 40 mm depending on the cross-section.
200.Not accounting for thermal expansion during alignment. A machine operating at 80 °C can move 0.5 mm from its cold position.
201.Over-tightening belts. A belt that is too tight damages the bearings of both the motor and the driven machine. Always use the deflection method.
202.Ignoring backlash when installing gears. Zero backlash causes overheating and knocking noise.
203.Installing a bearing by pressing on the wrong race. For a shaft mounting, force must be applied to the inner race only.
204.Forgetting the 125% rule for motor overload protection (CE Code Rule 28-300). This value is often asked on the exam.
205.Mixing units: never mix metric and imperial units in the same calculation. Convert first.
206.Neglecting to check the direction of rotation before final coupling. A three-phase motor can run in the wrong direction if the phases are reversed.

Summary

Power is the product of torque and angular velocity: P = T × Ω.
The transmission ratio is inversely proportional to diameters or numbers of teeth.
Belts transmit power by friction (V-belts, flat belts) or by meshing (timing belts). Tension is checked using the deflection method.
Chains transmit power by positive meshing. The recommended sag is 2 to 4% of the centre distance.
Gears offer high efficiency (95-98%). Backlash is essential for proper operation.
Couplings compensate for alignment defects. Dial indicator or laser alignment is a key skill.
Reducers multiply torque while reducing speed. Output torque = input torque × ratio × efficiency.
The Canadian Electrical Code (Rule 28-300) requires protection at 125% of full-load current for motors.
CSA Z432 governs machine guards; CSA Z460 governs lockout.
Rotor balancing follows ISO 1940 with G qualities ranging from G 0.4 to G 6.3 depending on the application.

Self-Assessment Questions

221.A 10 kW motor runs at 1450 RPM. What is the torque on the shaft?
222.A driving pulley of 200 mm diameter rotates at 1200 RPM. The driven pulley has a diameter of 500 mm. What is the output speed?
223.A 30:1 reducer with 85% efficiency receives an input torque of 50 N·m. What is the output torque?
224.What is the recommended sag for a chain with a centre distance of 600 mm?
225.What is the alignment tolerance for a machine running at 3000 RPM?
226.What percentage of overload protection is required by the CE Code for a continuously rated motor?

(Answers: 1. 65.9 N·m; 2. 480 RPM; 3. 1275 N·m; 4. 12 to 24 mm; 5. 0.05 mm parallel, 0.05 mm/100 mm angular; 6. 125%)

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