Concrete Placement and Formwork Coordination
Red Seal Practice study guide with diagrams.
Concrete Placement and Formwork Coordination
Introduction to the Reinforcing Steel Worker's Role in Coordination
The reinforcing steel worker (rebar installer) never works in isolation. On a reinforced concrete job site, rebar placement must be synchronized with formwork, pouring, and concrete curing. The National Building Code of Canada (NBC) and CSA A23.1/A23.2 standards (Concrete: Constituents and Execution of Work / Test Methods) define specific requirements that govern this coordination. Your role involves anticipating interferences, checking tolerances, and ensuring that reinforcement is in its final position before the concrete arrives.
This chapter covers coordination principles, volume and pressure calculations, safety rules, dimensional tolerances, and classic exam pitfalls.
2. Work Sequencing: Formwork, Reinforcement, Concrete
2.1 Logical Order of Operations
The typical sequence on a reinforced concrete job site is as follows:
Critical point: the reinforcing steel worker must finish their work before the final inspection. Any modification to the reinforcement after pouring has begun is prohibited, except under the direction of an engineer.
2.2 Coordination with Formwork
The formwork must be designed to resist the lateral pressure of fresh concrete. This pressure depends on:
Lateral pressure formula (CSA A23.1 simplified method) :
For concrete of normal consistency (slump ≤ 100 mm), the maximum lateral pressure p (in kPa) is approximately:
p = 23.5 × h
where h is the height of fresh concrete above the point in question (in meters). This formula assumes full hydrostatic pressure, which is the case if the concrete is poured rapidly or if the temperature is low.
Example: For a 3 m high wall poured in a single lift, the maximum pressure at the bottom of the formwork is:
p = 23.5 × 3 = 70.5 kPa
The formwork must therefore be designed to resist this pressure, plus dynamic loads (vibration, impact).
2.3 Reinforcement Positioning Tolerance Table (CSA A23.1, Table 7)
| Element | Allowable Tolerance |
|---|---|
| Nominal cover (c) | ± 10 mm (if c ≤ 100 mm) |
| Nominal cover (c) | ± 15 mm (if c > 100 mm) |
| Spacing between bars | ± 15 mm |
| Bar position within a section | ± 15 mm relative to the plane |
| Stirrup height | ± 10 mm |
| Bar offset (splices) | ± 50 mm along the axis |
Golden rule: the minimum cover must never be less than the specified value minus the tolerance. For example, if the nominal cover is 50 mm, the actual cover must be ≥ 40 mm.
3. Volume and Proportioning Calculations
3.1 Concrete Volume for a Section
The volume of concrete required for a slab, beam, or wall is calculated by:
V = L × W × H
where L = length, W = width, H = height (in meters). The result is in cubic meters (m³).
Example: A slab of 12 m × 8 m × 0.2 m:
V = 12 × 8 × 0.2 = 19.2 m³
Important: you must add a waste factor of 5 to 10% to account for losses, overflows, and formwork irregularities. In the example above, with 8% waste:
V_total = 19.2 × 1.08 = 20.74 m³
3.2 Number of Bars and Spacing
For a slab, the bar spacing is given by:
s = (b – 2 × c) / (n – 1)
where b = section width, c = cover, n = number of bars.
Example: A beam 400 mm wide, 40 mm cover, with 5 longitudinal bars:
s = (400 – 2 × 40) / (5 – 1) = 320 / 4 = 80 mm
Verification: the clear spacing between bars must be ≥ 1.4 × the maximum nominal aggregate size (generally 20 mm, therefore spacing ≥ 28 mm) and ≥ 25 mm. Here, 80 mm is acceptable.
3.3 Development and Lap Length
The development length (ld) is the anchorage length required to transfer the stress from the steel to the concrete. According to CSA A23.3 (Design of Concrete Structures), the basic development length for a bar in tension is:
ld = (0.45 × fy × db) / (√f'c)
where:
Example: 20 mm bar (db = 20), fy = 400 MPa, f'c = 30 MPa:
ld = (0.45 × 400 × 20) / √30 = 3600 / 5.48 = 657 mm
This value must be multiplied by correction factors (epoxy coating, spacing, etc.). For the exam, remember the basic formula and the main factors.
Lap length: for bars in tension, the minimum lap length is 1.3 × ld (if the concrete surface area is sufficient). For bars in compression, it is 0.071 × fy × db (but never less than 300 mm).
4. Concrete Pressure and Formwork Design
4.1 Factors Influencing Pressure
The maximum lateral pressure on formwork is reached when the concrete is still fluid. Key factors:
4.2 Pressure Formula for Self-Consolidating Concrete (SCC)
For self-consolidating concrete (SCC), the lateral pressure is considered fully hydrostatic:
p = ρ × g × h
where ρ = concrete density (≈ 2400 kg/m³), g = 9.81 m/s², h = drop height.
In practical units: p (kPa) = 23.5 × h (m).
Example: A 4 m high wall poured with SCC:
p = 23.5 × 4 = 94 kPa
This is a very high pressure. The formwork must be reinforced accordingly, with appropriately spaced shores and ties.
4.3 Formwork Tie Spacing
Ties (threaded rods) hold formwork panels together. The maximum tie spacing is calculated based on the lateral pressure and the tie capacity.
Formula:
Spacing (m) = √(Tie capacity (kN) / (Pressure (kPa) × Influence width (m)))
Example: Tie with a capacity of 50 kN, lateral pressure of 70 kPa, influence width of 0.5 m:
Spacing = √(50 / (70 × 0.5)) = √(50 / 35) = √1.43 = 1.19 m
Therefore, a maximum spacing of 1.1 m is prudent.
5. Cover and Chairs
5.1 Cover Requirements (CSA A23.1, Table 6)
Cover protects the steel against corrosion and ensures stress transfer. Minimum values are:
| Element | Minimum Cover (mm) |
|---|---|
| Concrete cast against the ground | 75 |
| Concrete exposed to weather (walls, beams) | 50 |
| Non-exposed concrete (interior) | 30 |
| Slabs and walls (main bars) | 20 (if non-exposed) |
| Stirrups and secondary reinforcement | 15 (if non-exposed) |
Exam rule: the minimum cover for a bar exposed to weather is 50 mm. For footings cast against the ground, it is 75 mm.
5.2 Types of Chairs
Chairs maintain the cover. They must be:
Common pitfall: wooden chairs are prohibited (they decompose and create voids). Metal chairs must not be in contact with the exterior surface of the concrete (corrosion risk).
6. Vibration and Concrete Consolidation
6.1 Role of Vibration
Vibration removes air bubbles and ensures complete cover of the reinforcement. Insufficient vibration creates honeycombing (voids) around the bars. Excessive vibration causes segregation (separation of aggregates and paste).
6.2 Vibration Rules
Critical point for the reinforcing steel worker: vibration must never displace the reinforcement. If the vibrator strikes a bar, it can move it and reduce the cover. The reinforcing steel worker must check bar positions after vibration if the pour is visible.
7. Coordination with Other Trades
7.1 Blockouts and Penetrations
Before pouring, the reinforcing steel worker must verify that blockouts (holes, openings) for electrical conduits, plumbing, and ventilation are in place. Reinforcement must not be cut to pass conduits without an engineer's approval.
Rule: if a conduit must pass through a beam, it must be placed in the shear zone with additional reinforcement (closely spaced stirrups). Cutting a main bar is prohibited without calculations.
7.2 Anchors and Inserts
Inserts (threaded plates, dowels) must be welded or attached to the reinforcement before pouring. Their position must be verified with a laser level or theodolite.
Tolerance: ± 5 mm for the position of critical inserts (heavy equipment).
8. Safety During Pouring
8.1 Main Hazards
8.2 Safety Rules (Canada Labour Code, Canada Occupational Health and Safety Regulations)
9. Inspection and Documentation Requirements
9.1 Pre-Pour Inspection
The reinforcing steel worker must be present during the final inspection. Checkpoints include:
9.2 Inspection Reports
The report must include:
10. Steel Quantity Calculations
10.1 Linear Mass of Bars
The mass of a bar per linear meter is:
m = (π × db² / 4) × ρ_steel
where ρ_steel = 7850 kg/m³.
In practice, the simplified formula is used:
m (kg/m) = db² / 162
where db is in millimeters.
Example: 20 mm bar:
m = 20² / 162 = 400 / 162 = 2.47 kg/m
10.2 Table of Common Linear Masses
| Diameter (mm) | Mass (kg/m) |
|---|---|
| 10 | 0.617 |
| 12 | 0.888 |
| 15 | 1.39 |
| 20 | 2.47 |
| 25 | 3.85 |
| 30 | 5.56 |
| 35 | 7.56 |
Exam tip: memorize the values for 10, 20, and 25 mm. The others can be derived by proportion (mass varies with the square of the diameter).
10.3 Calculating the Total Weight of an Element
Example: A beam contains 8 bars of 25 mm diameter, each 6 m long.
Mass per bar: 3.85 kg/m × 6 m = 23.1 kg
Total mass: 23.1 × 8 = 184.8 kg
Add 5% for offcuts and ties: 184.8 × 1.05 = 194 kg.
11. Pitfalls to Avoid
12. Summary
Formulas to memorize for the exam:
| Formula | Usage |
|---|---|
| V = L × W × H | Concrete volume |
| p = 23.5 × h | Lateral pressure (kPa) |
| ld = (0.45 × fy × db) / √f'c | Development length |
| m = db² / 162 | Linear mass (kg/m) |
| s = (b – 2c) / (n – 1) | Bar spacing |
| Tie spacing = √(Capacity / (p × width)) | Formwork design |
13. Self-Assessment Questions
14. Normative References
These standards are cited in the Red Seal exam. You must know the relevant section numbers (for example, CSA A23.1, Section 7 for tolerances, Section 6 for cover).
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