Pressure and Flow Calculations for Gas Systems
Red Seal Practice study guide with diagrams.
Pressure and Flow Calculations for Gas Systems
Introduction
This chapter covers the fundamental principles of pressure and flow calculations applicable to gas systems, as required by the Canadian Natural Gas and Propane Installation Code (CSA B149.1). As a Class A gasfitter, you must master these calculations to properly size piping, verify allowable pressure drops, and ensure the safe operation of appliances. The Red Seal exam places strong emphasis on your ability to apply these formulas in practical contexts.
Units of Measurement and Conversions
Pressure Units
Pressure is a force applied over a surface. In the gas trade, several units are used that you must be able to convert quickly:
| Unit | Symbol | Equivalence |
|---|---|---|
| Pascal | Pa | 1 Pa = 1 N/m² |
| Kilopascal | kPa | 1 kPa = 1000 Pa |
| Megapascal | MPa | 1 MPa = 1000 kPa |
| Bar | bar | 1 bar = 100 kPa |
| Pounds per square inch | psi | 1 psi = 6.895 kPa |
| Inches of water column | in H₂O | 1 in H₂O = 0.249 kPa |
| Millimetres of mercury | mmHg | 1 mmHg = 0.133 kPa |
Essential conversions to memorize:
Flow Units
Gas flow is generally expressed in:
Conversion factor: 1 m³/h = 35.31 ft³/h
Reference Conditions
Gas flow rates are always expressed at reference conditions:
Since gas is compressible, its volume varies with temperature and pressure. It is crucial to always bring measurements back to reference conditions to compare flow rates.
Absolute Pressure and Gauge Pressure
Fundamental Distinction
Formula: P_absolute = P_gauge + P_atmospheric
Standard atmospheric pressure is 101.325 kPa at sea level. It decreases with altitude (approximately 1 kPa per 100 m of elevation).
Practical Application
In sizing calculations, gauge pressure is generally used for pressure drops, but absolute pressure comes into play in:
Ideal Gas Law
Statement
The relationship between pressure, volume, and temperature of a gas is described by:
P × V = n × R × T
Where:
Combined Gas Law
For a fixed quantity of gas, you use:
P₁ × V₁ / T₁ = P₂ × V₂ / T₂
This relationship allows you to correct gas volumes to reference conditions.
Calculation Example
A tank contains 10 m³ of natural gas at 200 kPa (gauge) and 25 °C. What would the volume be at reference conditions (101.325 kPa, 15 °C)?
Pressure Drop in Piping
General Principles
Pressure drop is the loss of pressure due to gas friction against the pipe walls. It depends on:
Allowable Pressure Drop
CSA B149.1 requires that the pressure drop between the supply point and the appliance not exceed the following values:
| System Type | Maximum Allowable Drop |
|---|---|
| Low pressure (less than 7 kPa) | 0.5 kPa (2 in H₂O) |
| Medium pressure (7 to 100 kPa) | 10% of supply pressure |
| High pressure (more than 100 kPa) | 10% of supply pressure |
Important note: For gas appliances, the minimum pressure required at the appliance inlet is generally 1.75 kPa (7 in H₂O) for natural gas and 2.75 kPa (11 in H₂O) for propane, unless otherwise specified by the manufacturer.
Equivalent Length
Equivalent length accounts for the additional losses caused by fittings, elbows, valves, and other accessories. You add the equivalent lengths of each fitting to the actual pipe length.
Typical equivalent length values (in metres of straight pipe):
| Fitting | 1/2 in | 3/4 in | 1 in | 1 1/4 in | 1 1/2 in | 2 in |
|---|---|---|---|---|---|---|
| 90° elbow | 0.3 | 0.4 | 0.5 | 0.7 | 0.8 | 1.0 |
| 45° elbow | 0.2 | 0.2 | 0.3 | 0.3 | 0.4 | 0.5 |
| Tee (straight through) | 0.2 | 0.2 | 0.3 | 0.3 | 0.4 | 0.5 |
| Tee (branch) | 0.6 | 0.8 | 1.0 | 1.3 | 1.5 | 2.0 |
| Shut-off valve | 0.3 | 0.4 | 0.5 | 0.7 | 0.8 | 1.0 |
| Plug cock | 0.6 | 0.8 | 1.0 | 1.3 | 1.5 | 2.0 |
Pipe Sizing Methods
Pressure Drop Method (CSA B149.1)
The code provides capacity tables for piping based on:
Capacity Table — Natural Gas (supply pressure: 2.1 kPa, drop: 0.5 kPa)
Capacity in m³/h for different lengths:
| Diameter | 15 m | 30 m | 45 m | 60 m | 90 m | 120 m |
|---|---|---|---|---|---|---|
| 1/2 in | 2.8 | 1.9 | 1.5 | 1.3 | 1.0 | 0.9 |
| 3/4 in | 5.9 | 4.1 | 3.3 | 2.8 | 2.3 | 2.0 |
| 1 in | 11.1 | 7.7 | 6.2 | 5.4 | 4.3 | 3.7 |
| 1 1/4 in | 22.7 | 15.8 | 12.8 | 11.0 | 8.9 | 7.7 |
| 1 1/2 in | 34.0 | 23.7 | 19.2 | 16.5 | 13.4 | 11.6 |
| 2 in | 65.2 | 45.4 | 36.8 | 31.7 | 25.7 | 22.2 |
These values are provided for reference only. Always use the current CSA B149.1 tables during the exam.
Formula Calculation Method
For medium and high pressure systems, you can use the simplified formula:
Q = C × √(ΔP × D⁵ / (L × G))
Where:
Sizing Procedure
Relative Density and Correction
Relative Density of Gases
Relative density (or specific gravity) is the ratio of the gas density to that of air under the same conditions:
| Gas | Relative Density |
|---|---|
| Air (reference) | 1.00 |
| Natural gas | 0.60 to 0.65 |
| Propane | 1.52 |
| Butane | 2.00 |
Effect on Capacity
A gas denser than air (such as propane) requires a larger pipe for the same volumetric flow rate. The capacity of a pipe is inversely proportional to the square root of the relative density:
Q₂ = Q₁ × √(G₁ / G₂)
Example
A pipe carries 10 m³/h of natural gas (G = 0.60). What would its capacity be with propane (G = 1.52)?
Q_propane = 10 × √(0.60 / 1.52) = 10 × 0.628 = 6.28 m³/h
Altitude Correction
Effect of Altitude
At high altitude, atmospheric pressure is lower, which affects:
Correction Factor
CSA B149.1 requires a correction for installations located above 700 m in altitude. The correction factor is:
F = 1 - (0.0001 × (Altitude - 700))
Application
For an installation at 1500 m altitude:
F = 1 - (0.0001 × 800) = 1 - 0.08 = 0.92
The pipe capacity must be multiplied by this factor, or the load must be divided by this factor.
Heating Value and Equivalent Flow
Heating Value
Heating value is the amount of heat released by the complete combustion of a volume of gas:
| Gas | Higher Heating Value |
|---|---|
| Natural gas | 37.3 MJ/m³ |
| Propane | 93.2 MJ/m³ |
| Butane | 121.8 MJ/m³ |
Flow Conversion
To compare appliances operating on different gases, you use the equivalent flow rate:
Q_equivalent = Q × (HV_gas / HV_reference)
Example
An appliance consumes 2 m³/h of propane. What natural gas flow rate would be equivalent in terms of power?
Q_NG = 2 × (93.2 / 37.3) = 2 × 2.5 = 5 m³/h
Applicable CSA B149.1 Rules
Rule 6.2 — Pressure Drop
Rule 6.2 of CSA B149.1 states that the pressure drop in piping must not exceed the specified allowable values. The gasfitter must ensure that the pressure at the point of use is sufficient for the operation of the appliances.
Rule 6.3 — Pipe Sizing
This rule requires that piping be sized according to the code tables or by calculation, taking into account:
Rule 6.4 — Gas Velocity
The velocity of gas in piping must not exceed 20 m/s to avoid noise and excessive erosion.
Rule 6.5 — Test Pressure
Piping must be subjected to pressure tests before being put into service:
Practical Applications
Sizing a Main Supply Pipe
Problem: A residence must supply the following appliances:
The main pipe is 25 m long with 4 — 90° elbows and 2 tees (branch). Supply pressure: 2.1 kPa.
Solution:
Verifying Residual Pressure
Problem: The 1 1/4 in pipe from the previous example supplies the most distant appliance. Verify the pressure at this appliance.
Solution:
Pitfalls to Avoid
Unit Conversion Errors
Sizing Errors
Code Errors
Calculation Errors
Exam Tips
Problem-Solving Strategy
Key Points to Memorize
Time Management
Summary
Pressure and flow calculations are essential for the safe sizing of gas systems. The fundamental points to remember:
Regular practice of sizing problems is the best preparation for the exam. Redo the examples in this chapter without looking at the solutions, then check your results. Mastering these calculations will serve you not only for the exam, but also in your daily practice as a Class A gasfitter.
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